Question 1151273
<font color=black size=3>
Let's explore hint #2 that the tutor @ikleyn has provided.


Triangle ABC has base of BC = 2
Let h be the height of triangle ABC. It does not matter what h is for this thought experiment.
The area of triangle ABC is therefore, A = (1/2)*base*height = (1/2)*2*h = h.
Area of triangle ABC = h.


The base of triangle CDM is also 2, because C is the midpoint of BD, so BC = CD = 2.
The height of point M is half that of point A's height. Imagine that point A is (0, h). Through use of the midpoint formula, you'll find that the y coordinate of point M will be y = h/2.
So the height of triangle CDM is h/2.


area of triangle CDM = (1/2)*base*height
area of triangle CDM = (1/2)*2*(h/2)
area of triangle CDM = h/2
area of triangle CDM = (area of triangle ABC)/2
</font>