Question 1151208
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The 4-th term = sum of the first 4 terms  <U>MINUS</U>  sum of the first 3 terms = 


              = (4^2-3*4) - (3^2-3*3) = (16-12) - (9-9) = 4 - 0 = 4.    <U>ANSWER</U>



The n-th term = sum of the first "n" terms  <U>MINUS</U>  sum of the first (n-1) terms = 


             = (n^2-3*n) - ((n-1)^2-3*(n-1)).


Simplify to get the answer.
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