Question 1151187


let the number of chirps be {{{x}}} and the number of degrees {{{y}}}

At {{{104}}} chirps per minute, the temperature is  {{{63}}}°F. we have

 {{{x=104}}} and {{{y=63}}}

that is a point ({{{104}}} , {{{63}}}) on a line

At {{{176}}} chirps per minute, the temperature is {{{81}}}°F.

that is a point ({{{176}}} , {{{81}}}) on a line

the equation of a line is:

{{{y=mx+b}}} where {{{m}}} is a slope and {{{b}}} is y-intercept

using given points find slope {{{m}}}:

{{{m=(y[2]-y[1])/(x[2]-x[1])}}}

{{{m=(81-63)/(176-104)}}}

{{{m=18/72}}}.....simplify, divide both numerator and denominator by {{{18}}}

{{{m=1/4}}}

{{{y=(1/4)x+b}}} .......now use one point to find {{{b}}}

{{{63=(1/4)104+b}}}

{{{63=26+b}}}

{{{63-26=b}}}

{{{b=37}}}

your equation is:

{{{y=(1/4)x+37}}}



What is the temperature if you hear {{{148}}} chirps per minute?

given: {{{x=148}}}

{{{y=(1/4)148+37}}}

{{{y=37+37}}}

{{{y=74}}}=> the temperature is {{{74}}}°F


What is the temperature if you hear {{{84 }}}chirps per minute?

given: {{{x=84}}}

{{{y=(1/4)84+37}}}

{{{y=21+37}}}

{{{y=58}}}=> the temperature is {{{58}}}°F