<PRE><B>Question 1151139</B>
&lt;br&gt;
(1) Algebraically....&lt;br&gt;
Let x be his daughter&#39;s age; then x+27 is his age.&lt;br&gt;
In 10 years his daughter&#39;s age will be x+10 and his age will be x+37.&lt;br&gt;
At that time his age will be twice his daughter&#39;s age:&lt;br&gt;
{{{x+37 = 2(x+10)}}}&lt;br&gt;
Solve using basic algebra....&lt;br&gt;
(2) Using simple logical reasoning....&lt;br&gt;
The difference in their ages is 27 years.&lt;br&gt;
So when he is twice as old as his daughter, their ages will be 27 and 54.&lt;br&gt;
Since that will be 10 years from now, their current ages are 17 and 44.&lt;br&gt;
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