Question 1151117
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1/10.  It's just as likely that any one will show up first as any other.
Let p = the probability that any one will show up first:

P(#1  will show up first) = p
P(#2  will show up first) = p
P(#3  will show up first) = p
P(#4  will show up first) = p
P(#5  will show up first) = p
P(#6  will show up first) = p
P(#7  will show up first) = p
P(#8  will show up first) = p
P(#9  will show up first) = p
P(#10 will show up first) = p
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                          10p = 1
                            p = 1/10

Edwin</pre>