Question 106173
Let x=length
____y=width
____2(x+y)=perimeter


IF The length of a rectangle is 3 Inches more than its width, then,

{{{x=y+3}}}

IF The perimeter of the rectangle is 30 inches, then,

{{{2(x+y)=30}}}

Solving {{{2(x+y)=30}}},

{{{2(x+y)=30}}}
{{{(2(x+y))/(2)=30/2}}}
{{{x+y=15}}}

But, {{{x=y+3}}}, thus,


{{{y+3+y=15}}}
{{{y+y+3=15}}}
{{{2y+3=15}}}
{{{2y+3-3=15-3}}}
{{{2y+0=12}}}
{{{2y=12}}}
{{{2y/2=12/2}}}
{{{y=6}}}

Again, {{{x=y+3}}}, so,

{{{x=6+3=9}}}


Therfore, the length is 9 inches and the width is 6 inches.


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