Question 1151120

The base of a triangle is {{{x}}} cm long and its {{{altitude}}} is quarter the length of its base. 

base:{{{x}}} cm 

altitude:{{{(1/4)x}}} cm 

the  area of triangle:

{{{A=(1/2)*base*altitude}}}...substitute given

{{{A=(1/2)*x*(1/4)x}}}

{{{A=(1/8)*x^2}}}


If the triangle has an area of {{{12}}} cm^2, then

{{{12=(1/8)*x^2}}}

{{{12*8=x^2}}}

{{{96=x^2}}}

{{{x=sqrt(96)}}}



 the altitude of the triangle is {{{(1/4)x}}} cm=>{{{(1/4)sqrt(96)}}} cm=>{{{sqrt(96)/4}}} cm