Question 1151116

The perimeter of a rectangle is {{{8 }}}inches. 
{{{2(a+b)=8}}}
{{{a+b=4}}}
{{{a=4-b}}}.......eq.1

if the length {{{a}}} of the rectangle is {{{1}}} inch {{{more }}}than {{{twice}}} the {{{width}}} of the rectangle {{{b}}}, we have

{{{a=2b+1}}} ......eq.2

from  eq.1 and  eq.2 we have

{{{4-b=2b+1}}}
{{{4-1=2b+b}}}
{{{3=3b}}}
{{{b=1}}}

find {{{a}}}
{{{a=4-1}}}.......eq.1
{{{a=3}}}

 the length of the rectangle is {{{3}}} inches 
 the width of the rectangle is {{{1}}} inch