Question 1151064
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Here is a quick way to solve this problem and many similar problems without algebra -- if, of course, an algebraic solution is not required.<br>
(1) If all 24 students had purchased the yearbooks with pre-orders, the total cost would have been 24 times $38, or $912.  That is $975-$912 = $63 less than the actual total.
(2) Each full price order costs $45-$38 = $7 more than a pre-order.
(3) The number of full price orders required to make up the additional $63 is $63/$7 = 9.<br>
ANSWER:  9 students paid full price; so 24-9=15 students bought the yearbooks with pre-orders.<br>