<PRE><B>Question 1150998</B>
Bruslan is the architect in charge of designing a new elementary school.
 He has been told that each rectangular classroom should include 25m^2 of common space, plus 1.50m^2 per students for desks and chairs.
 If the maximum number of students in the class is 22, what is the least possible perimeter that the classroom design could have?
:
Find the total area of the class room.
25 + 22(1.5) = 58 sq/m
:
the area:
L * w = 58
replace w with (58/L)
w = {{{58/L}}}:
:
the perimeter
P = 2L + 2w 
P = 2L + 2(58/L}
Graph this equation
{{{ graph( 300, 200, -10, 20, -10, 50, 2x+2(58/x), 30.5) }}}
Graph shows Length for minimum perimeter occurs at 7.5 meters
therefore
{{{58/7.5}}} = 7.73 meters is the width
;
Min perimeter
P = 2(7.5) + 2(7.73)
P = 30.5 meters (green line)</PRE>