Question 1150896
 find the value of y if the mean of 22, 18, (2y+1) 10 and 20 is 25
{{{((22+18+(2y+1)+10+20))/6}}} = 25
Multiply both sides by 6
22+18+(2y+1)+10+20 = 6*25
2y + 71 = 150
2y = 150 - 71
2y =  79
y = 79/2
y = 39.5
:
:
check
2y+1: 2(39.5) + 1 = 80
{{{((22+18+80+10+20))/6}}} =
150/6 = 25