Question 1150872
.
<pre>

Use the formula for the area of a triangle 


    S = {{{(1/2)*a*b*sin(gamma)}}}


where "a" and "b" are two any side lengths of the triangle and  {{{gamma}}}  is the concluded angle between them.


From the formula,  {{{sin(gamma)}}} = {{{(2*S)/(a*b)}}} = {{{(2*49)/(17*16)}}} =  0.360.


Hence,  {{{gamma}}} = {{{arcsin(0.360)}}} = 0.368583 radians = 21.118 degrees.


The other possible value for the angle  {{{gamma}}}  is 180 degrees MINUS  21.118 degrees = 158.882 degrees.


<U>ANSWER</U>.  At given conditions, there are two possible values for the angle between the sides  

         21.118 degrees  OR  158.882 degrees (approximately).
</pre>

Solved.


---------------


It is just SECOND TWIN problem posted and solved today.


Please do not post twin problems.



Thank you very much.