Question 106165
FIND 3 CONSECUTIVE ODD INTEGERS SUCH THAT THE PRODUCT OF THE FIRST AND THIRD EXCEEDS THE SECOND BY 38.
------------
Let the integers be x, x+2, x+4
EQUATION:
x(x+4)= x+2+38
x^2+4x = x+40
x^2+3x-40 = 0

(x+8)(x-5) = 0
---
Positive answer:
x = 5
x+2 = 7
x+4 = 9
============
Cheers,
Stan H.