Question 1150767
{{{-12x -3 > 45}}}

{{{-12x -3 +3> 45+3}}}

{{{-12x > 48}}}

find {{{x}}} for what {{{-12x>48}}}

{{{x >48/-12}}}

{{{x <48/-12}}}

{{{x <-4}}}=>so, first number less than {{{-4 }}} is your answer: it is {{{x}}}={{{-5}}},{{{-6}}},{{{-7}}},{{{-8}}},{{{-9}}},...and so on

solutions interval: ({{{-infinity}}},{{{-4}}})

The correct answer is option "{{{x = -8}}}" because it is in solutions interval


check it:

{{{-12(-5) -3 > 45}}}

{{{60-3 > 45}}}

{{{57 > 45}}}=>true


{{{-12(-6) -3 > 45}}}

{{{72-3 > 45}}}

{{{69 > 45}}}=>true


{{{-12(-7) -3 > 45}}}

{{{84-3 > 45}}}

{{{81 > 45}}}=>true



{{{-12(highlight(-8)) -3 > 45}}}

{{{96-3 > 45}}}

{{{93 > 45}}}=>true