Question 1150725
<br>
Let the two roots be a and 3a.  The sum of the roots is 4a, and their product is 3a^2.<br>
By Vieta's Theorem, the quadratic is<br>
{{{x^2-4ax+3a^2}}}<br>
Then<br>
{{{p^2/q = (-4a)^2/(3a^2) = 16/3}}}<br>
ANSWER: p^2/q = 16/3<br>