Question 1150673
So, basically, when I placed these values on my TI-84 Plus graphing-calculator from Texas Instruments...

{{{Circle(0,0,12):Circle(2,0,8):Circle(1,3,6):Circle(8,9,3)}}}

...and then pressed the [ENTER] key, the graph automatically draws 4 different circles that are roughly interlinking each other—but in different sizes—and as I watched each step carefully, I have recognized that the smallest circle is the one with the radius of 3.

Although the center is located at coordinates (8, 9), the radius of the circle is measured 3 units for all 360 angles, no matter what the selected angle.

So, therefore, <I>(x + 8)² + (y - 9)² = 3</I> is the circle that has the smallest area, or radius.