Question 1150535
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Having nothing else given, an appropriate hypothesis is to assume that we have random discrete variable X = "the number of misprint" 

with integer random values which is uniformly distributed in the range [0,5] with the minimum value of 0 and the maximum value of 5.



Then the mean average  is exactly 2.5 = {{{(0+1+2+3+4+5)/6}}} = {{{15/6}}}, as the problem states, 

and  the condition becomes "consistent with the given part" and "self-closed".



Then the answer to question (a) is   P(X >= 3) = {{{3/6}}} = {{{1/2}}}  (X may have values of 3, 4 or 5) of 6 possible integer values from 0 to 5.  



Regarding your question (b), in your post it is formulated ambigously, and I do not understand its exact meaning.
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Solved.


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