Question 1150467
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Given: {{{t(n) = 10/3-n/3 = (10-n)/3}}}<br>
The alternate form will make it easier to find specified terms of the sequence.<br>
t(1): {{{t(1) = (10-1)/3 = 9/3 = 3}}}<br>
t(2), t(3): You can do those....<br>
t(n+1): {{{t(n+1) = (10-(n+1))/3 = (10-n-1)/3 = (9-n)/3}}}<br>
t(n+1)-t(n): {{{t(n+1)-t(n) = (9-n)/3-(10-n)/3 = ((9-n)-(10-n))/3 = (9-n-10+n)/3 = -1/3}}}<br>