Question 1150460
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Step 1) Remove 5 liters of wine. 
Mix A: 30 L of wine, 0 L of water
Mix B: 25 L of wine, 0 L of water


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Step 2) Add 5 liters of water.
Mix B: 25 L of wine, 0 L of water
Mix C: 25 L of wine, 5 L of water


Once we get to mix C, the fractional amount of wine is 5/6 because
25/30 = 5/6
The first fraction is in the form A/B
where 
A = amount of wine in liters
B = total amount of mixture (water+wine)
The second fraction is the reduced version of 25/30.


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Step 3) Remove 12 liters of liquid (from mix C) 


5/6 of the amount of mix C is composed of wine. So 5/6 of the amount of stuff we remove (12 L) is expected to be wine. The rest is water.

5/6 of 12 = (5/6)*12 = 10 liters of wine is removed
12-10 = 2 liters of water is removed as well


Mix C: 25 L of wine, 5 L of water
Mix D: 15 L of wine, 3 L of water
Going from mix C to mix D, I removed 10 liters of wine and removed 2 liters of water


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Step 4) Add 12 liters of pure water 
Mix D: 15 L of wine, 3 L of water
Mix E: 15 L of wine, 15 L of water



(15 L of water)/(15 L of water+15 L of wine) = 15/30 = 1/2 of mix E is water


<font size=4 color=red>Answer: 1/2</font>
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