Question 1150363
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The full number of all possible combinations in this case is the product  ALL = {{{C[5]^2}}}.{{{C[4]^3}}} = 10*4 = 40.


The number of all "good" combinations is  GOOD = {{{C[5-2]^2}}}.{{{C[4]^3}}} = {{{C[3]^2}}}.{{{C[4]^3}}} = 3*4 = 12,

    since we choose now 2 mathematicians from 3, excluding these two particular persons from 5 mathematicians.



So, the probability under the question is this ratio


    P = {{{GOOD/ALL}}} = {{{12/40}}} = {{{3/10}}}.    <U>ANSWER</U>
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Two notices to the post.



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    1.  This passage  "NO 2 PARTICULAR MATHMATICIANS INCLUDED TO COMMITE"

        I understand in this way "NO one of the 2 PARTICULAR MATHEMATICIANS INCLUDED TO COMMITTEE".



    2.  The right form of the word MATHEMATICIAN is as it is written in this line.

        The right form of the word COMMITTEE is as it is written in this line.


        Any/every other form, which you see in your post, is INCORRECT.
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