Question 1150222
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The idea of the solution is vary simple.


First, we should calculate the number of all possible groups of 6 numbers, selected from  48 numbers.

      This number is  {{{C[48]^6}}} = {{{((48*47*46*45*44*43)/(1*2*3*4*5*6))}}} = 12271512.



Next we should calculate the number of all possible groups ot 6 numbers, that contain 4 particular numbers.

      This numbers is  {{{C[44]^2}}} = {{{(44*43)/2}}} = 946


(since we can combine any of 2 remained 48-4 = 44 numbers with 4 particular numbers).



Finally, the desired probability is the ratio  P = {{{946/12271512}}} = {{{1/12972}}}.    <U>ANSWER</U>
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Solved.