Question 1150103
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When the equations are given in this form, elimination is (for me) by far the easiest way to go.<br><pre>
   6x - 3y =   5
 -12x + 6y = -15

Double the first equation to get an equation with "12x"; then adding the two equations will eliminate x:

  12x - 6y =  10
 -12x + 6y = -15
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         0 = -5

That equation is FALSE; that means the system has 0 solutions.<br>