Question 1150087
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(1) Algebraically....<br>
Switch the x and y and solve for the new y:<br>
{{{x = (y-7)^2}}}
{{{sqrt(x) = y-7}}}
{{{y = sqrt(x)+7}}}<br>
(2) Using the concept that an inverse function "gets you back where you started"....<br>
Look at what the given function does to the input:
(a) subtract 7
(b) square<br>
The inverse function, to get you back where you started, has to do the opposite operations in the opposite order:
(a) take the square root
(b) add 7<br>
ANSWER: The inverse function is {{{y = sqrt(x)+7}}}<br>