Question 1150071
Find the slope of the line tangent to the following at point where x = 2:
〖f(x)=e〗^(-0.1x^2+2x-3)
--------------------------
{{{f(x) = e^(-0.1x^2+2x-3)}}}

f'(x) = {{{e^(-0.1x^2+2x-3)*(-0.2x + 2)}}}
f'(x) = {{{(-0.2x + 2)*e^(-0.1x^2+2x-3)}}}
--------
Sub 2 for x