Question 1150056
If the width is w, the length is w+4 so we have w(w+4)=77 

{{{w^2+4w=77}}}

{{{w^2+4w-77=0}}} 

{{{(w-7)(w+11)=0}}} A width can’t be negative so we have w=7 and w+4=11 so the dimensions of the rectangle are 7 and 11.