Question 1149878
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Let x be "another" integer.


Then the "first" integer is 2x-6.


   x^2 + (2x-6)^2 = 296


   x^2 + 4x^2 - 24x + 36 = 296

   5x^2 - 24x - 260 = 0


    {{{x[1,2]}}} = {{{(24 +- sqrt(24^2 + 4*5*260))/(2*5)}}}.


     {{{x[1]}}} = 10.

     The other root is negative.


<U>Answer</U>.  The numbers are 10  and 2*10-6 = 14.    <U>ANSWER</I>
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Solved.