Question 1149873

A flower bed is in the shape of a triangle: so,  the perimeter is 

{{{P=a+b+c}}} where {{{a}}} is the shortest side, and {{{b}}} is other side twice the length of the shortest side and the third side {{{c}}} is {{{16}}} feet more than the length of the shortest side. 

so, sides are:

{{{a}}}
{{{b=2a}}}
 {{{c=a+16}}}

Find the dimensions if the perimeter is {{{172}}} feet.

given:

{{{P=172}}}, {{{a}}}, {{{b=2a}}},{{{c=a+16}}}


so, we have

{{{172=a+2a+a+16}}} .........solve for {{{a}}}


{{{172=4a+16}}}


{{{172-16=4a}}}


{{{156=4a}}}


{{{156/4=a}}}


{{{a=highlight(39)}}}->the shortest side


{{{b=2a}}}->{{{b=highlight(78)}}}->other side


{{{c=a+16}}}->{{{c=39+16}}}->{{{c=highlight(55)}}}->the third side


check the perimeter:

{{{172=a+b+c}}}

{{{172=39+78+55}}}

{{{172=172}}}