Question 1149843
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<pre>

The setup is this equation


    {{{1/x}}} + {{{1/(x+5)}}} = {{{1/6}}},


where x is the number of days under the question.


Simplify and solve step by step.  The first step is to multiply equation (1) by 6x(x+5).


    6(x+5) + 6x = x*(x+5)

    6x + 30 + 6x = x^2 + 5x

    x^2 - 7x - 30 = 0.

    (x-10)*(x+3) = 0.


There are two roots, x= 10 and x= -3;  only positive root makes sense.

So, only the root x= 10 satisfies the problem's conditions.


<U>Answer</U>.   It will take Onduso 10 days to do the work alone.
</pre>

Solved.


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To see many other similar solved problems by the same method, look into the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/Rate-of-work-word-problems/Using-quadr-eqns-to-solve-word-problems-on-joint-work.lesson>Using quadratic equations to solve word problems on joint work</A> 

in this site.


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lesson is the part of this textbook under the topic 
"<U>Rate of work and joint work problems</U>" &nbsp;of the section &nbsp;"<U>Word problems</U>".



Save the link to this online textbook together with its description


Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson


to your archive and use it when it is needed.