<PRE><B>Question 1149636</B>
6e^-0.1t = 2
:
e^-0.1t = 2/6 = 1/3
:
take the natural log of both sides
:
-0.1t = ln(1/3)
:
-0.1t = −1.0986
:
t = −1.0986/-0.1 = 10.986
:
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in approimately 11 hours another injection must be given
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: 
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