Question 1149406
<pre>
{{{f(x-f(y)^"") = f(x)-x*f(y)}}}, {{{f(0)=3}}}

let x=2016 and y=0

{{{f(2016-f(0)^"") = f(2016)-2016*f(0)}}}

{{{f(2016-3) = f(2016)-2016*3}}}

{{{f(2013) = f(2016)-6048}}}

{{{6048 = f(2016)-f(2013)}}}

Answer = 6948

Edwin</pre>