Question 1149546
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To isolate x, we need to use the rule that if {{{y = ln(x)}}}, then {{{e^y = x}}}


So,


{{{ln(5x-2) = 2}}} starting equation


{{{5x-2 = e^2}}} use the rule mentioned above


{{{5x = e^2+2}}} add 2 to both sides


{{{x = (e^2+2)/5}}} divide both sides by 5


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Extra info:
The letter 'e' represents the constant 2.71828182846
It is similar to how pi = 3.1415926535898
Both values have no pattern to the digits and the decimal digits go on forever, which makes those decimal representations to be approximations.	
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