Question 1149537
A ball is kicked upwards from a rooftop 5m above the ground. It reaches a maximum height of 8m. At 3s, the ball is 1 m above the ground. Initial kick is at 0s and the ball follows a quadratic trajectory, at what time does the ball reach the maximum height?
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The formula is {{{h(t) = at^2 + v[0]t + h[0]}}}
a = acceleration due to gravity, {{{v[0]}}} is initial velocity and {{{h[0]}}} is height at t = 0 ( = 5 meters).
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I get interruptions, I'll finish this later.