Question 1149521
<pre>
-1   |   1   3   -2   -4
     |      -1   -2    4
     |_________________________
         1   2   -4    0
</pre>
{{{h(x)=(x+1)(x^2+2x-4)}}}



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Quadratic's roots,
{{{x=(-2+- sqrt(4+4*4))/2}}}

{{{(-2+- 2*sqrt(5))/2}}}

{{{-1+- sqrt(5)}}}

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{{{h(x)=(x+1)(x-(-1+sqrt(5)))(x-(-1-sqrt(5)))}}}

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