<PRE><B>Question 15536</B>
The length of a rectangle is 2cm less than 7 times the width. The perimeter is 60cm. Find the width and length.
let length be =L
let width be  = W
7 times width =7W
 2 cm. less than above = 7W-2 = L
  perimeter =2L+2W = 60 
  2*(7W-2)+2W = 60 
   14W+2W=60+2*2=64
16W = 64 
  W =64/16 = 4
  L=7*4-2 = 26
  SECOND PROBLEM

The first side of a triangle is 8m shorter than the second side. The third side is 4times as long as the first side. The perimeter is 26m. Find the length of each side. 
Let the first side =x
let the second side =y
let the third side =z
8m shorte than second side = y-8 = x OR y = x+8
4 times the first side =4*x= z
perimeter =x+y+z = 26 
x+(x+8)+4*x = 26
x+x+4x=26-8 = 18
6x = 18 
x=18/6 = 3
y= 3+8 = 11
z=4*3 = 12 




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