Question 1149366
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If we are given only the angle between the two vectors, we can determine the magnitude of the resultant vector; but we have no information that allows us to determine that vector.<br>
For simplicity, let vector p be horizontal, with vector q making an angle of 60 degrees with p.  Then the x component of the resultant vector is<br>
{{{20+8*cos(60) = 20+8(1/2) = 20+4 = 24}}}<br>
and the y component is<br>
{{{8*sin(60) = 8*(sqrt(3)/2) = 4*sqrt(3)}}}<br>
Then the magnitude of the resultant vector, using the Pythagorean Theorem, is<br>
{{{sqrt((24)^2+(4*sqrt(3))^2)}}}<br>
I leave it to you to do the calculation....<br>