Question 1149262
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Here is a very different method for solving the problem....<br>
The ratio of the distances is 196/161 = 28/23.<br>
Since the times are the same, the ratio of the speeds is also 28/23.<br>
You want two speeds that are in that same ratio and differ by 10.<br>
So look for a fraction equivalent to 28/23 in which the numerator is 10 more than the denominator.<br>
In 28/23, the numerator is 5 more than the denominator.<br>
So multiply numerator and denominator by 2 to find the rates of the two vehicles.<br>
28/23 = 56/46<br>
The rate of the car is 46mph; the rate of the motorcycle is 56mph.<br>