Question 1149197
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Standard algebraic solution method: work with the fractions of the work done in 1 minute.<br>
Let x = number of minutes for faster worker
Then x+33 = number of minutes for slower worker<br>
Faster worker does 1/x of the job in 1 minute
Slower worker does 1/(x+33) of the job in 1 minute
Together they do 1/18 of the job in 1 minute<br>
{{{1/x + 1/(x+33) = 1/18}}}<br>
Solve by any method you like.<br>
(Presumably you are working this problem to learn HOW to solve problems like this; in that case, the answers should be "nice" numbers.  These answers are not "nice"; I suspect the numbers you show are wrong....)<br>