Question 1149154
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<pre>

The distance formula


    {{{(b-3)^2}}} + {{{(-2-1)^2}}} = {{{(5-b)^2}}} + {{{(2-1)^2}}}


    {{{(b-3)^2}}} + 9       = {{{(5-b)^2}}} + 1

    {{{b^2 - 6b + 9 + 9}}}       = {{{25 - 10b + b^2 + 1}}}

    -6b + 18         = 26 - 10b

     10b - 6b        = 26 - 18

     4b              = 8

      b              = 8/4 = 2.     <U>ANSWER</U>
</pre>

Solved.