Question 1149117
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1st coin: 10m to the coin and 10m back to the basket = 20m
2nd coin: 20m to the coin and 20m back to the basket = 40m
3rd coin: 30m to the coin and 30m back to the basket = 60m
...
80th coin: 800m to the coin and 800m back to the basket = 1600m<br>
Total distance: (20+40+60+...+1600)m<br>
Use the formula for the sum of an arithmetic sequence:<br>
{{{S = n((a1+an)/2) = 80((20+1600)/2) = 80(810) =64800}}}<br>
ANSWER: 64,800 meters<br>