<PRE><B>Question 1149102</B>
Need the mean and sd
mean is 12.11, THIS IS THE POINT ESTIMATE
sd s is 0.528
the half-interval is tdf=9, appropriate CI wished*s/sqrt(n)
so for 90% where t=1.833
the half-interval is 1.833*0.528/sqrt(10)=0.3061
the 90% CI for the mean is mean+/-0.31 or (11.80, 12.42)

95% is done the same way with t=2.262
99% has t=2.821
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