Question 105871


{{{4x+5y=11}}}

{{{y=3x-13 }}}   you can take this value of {{{y}}} and substitute it in first expresion, so you can find {{{x}}}

{{{4x + 5(3x - 13) = 11}}}

{{{4x + 15x - 65 = 11}}}

{{{19x = 11 + 65}}}

{{{19x = 76}}}

{{{x = 76/19}}}

{{{x = 4}}}

now, go back to
{{{y = 3x - 13}}}

and find {{{y}}}

{{{y = 3*4 - 13}}}

{{{y = 12 - 13}}}

{{{y = -1}}}