Question 1148927
the three circles show a common intersection with 7
with English and history it is 13, but 7 are common to all three, so it is 6 with E and H.
with E and L it is 16, but 7 common so it is 9 for E and L
with L and H it is 18 but 7 are common so it is 11 for H and L
That leaves 25 for E, 11 for L, and 25 for H
All the numbers add to 94, so 6 take none of the three
One of the three would be 61.

One has to assume that 2 together must count the fact that it includes all three or the language number doesn't work.