Question 105612
Each Frisbee toss is an independent event.(Three tosses) 
Each Frisbee toss can be either 0, 1, 5, or 10 points (Four values at each toss)
If I first toss a 0, then my next toss could be four possible values (0,1,5,10). Since I have 4 possible first tosses, I have 4x4 possible two toss pairs for first and second tosses ((0,0),(0,1),...,(10,5),(10,10)). Same for the third toss, for each of the 16 two toss pairs, I have 4 possible values or 4x16=64 possible three toss values((0,0,0),(0,0,1),...,(10,10,5),(10,10,10)). 
Or mathematically
Round 1 : {{{4^1=4}}} 1 toss combinations
Round 2 : {{{4^2=16}}} 2 toss combinations
Round 3 : {{{4^3=64}}} 3 toss combinations