Question 1148837
x = the price of an adult ticket.
y = the price of a child ticket.


you have two equations that need to be solved simultaneously.
they are:
3x + 2y = 78.05
2x + 3y = 73.90


multiply both sides of the first equation by 2 and multiply both sides of the second equation to 3 to get:
6X + 4Y = 156.10
6X + 9Y = 221.70
subtract the first equation from the second to get:
5y = 65.60
solve for y to get:
y = 13.12
replace y in the first original equation of 3x + 2y = 78.05 and solve for x to get:
x = 17.27


you have:
x = 17.27
y = 13.12


go back to the original two equations to get:
3x + 2y = 78.05 becomes 51.81 + 26.24 = 78.05 which becomes 78.05 = 78.05, which is true.
2x + 3y = 73.90 becomes 34.54 + 39.36 = 73.90 which becomes 73.90 = 73.90, which is true.


both original equations are true when x = 17.27 and y = 13.13.
this confirms those values are good.


your solution is that the price of an adult ticket is 17.27 and the price of a child ticket is 13.12.