Question 1148829
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Let x be the initial volume of water in Tank B.

Then initial volume in Tank A was 4x.


The equation is


    4x - 1.485 = x + 1.485       liters

    3x = 1.485 + 1.485 = 2.970   liters

     x = 2.970/3  = 0.99         liters


<U>ANSWER</U>. At the end, tank A contained  4x-1.485 = 4*0.99-1.485 = 2.475 liters = 2 liters and 475 milliliters.


         At the end, tank B contained  the SAME amount of water, as tank A contained at the end, i.e. 2 liters and 475 milliliters.
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Solved, answered, explained and completed.