Question 1148809
{{{ 1.25h = h*( 1 + r )^5 }}}
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The 5-day growth factor is 1.25
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{{{ 1.25 = ( 1 + r )^5 }}}
{{{ log( 1.25 ) = 5*log( 1 + r ) }}}
{{{ .09691 = 5*log( 1 + r ) }}}
{{{ log( 1 + r ) = .019382 }}}
{{{ 10^.019382 = 1 + r }}}
{{{ 1.04564 = 1 + r }}}
{{{ r = .04564 }}}
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{{{ k*h = h*( 1 + r )^1 }}}
{{{ k = 1 + .04564 }}}
The growth factor for 1 day is 1.04564 
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The % change in 1 day is 4.564%
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{{{ f(t) = f(0)*( 1 + .04564 )^t }}}
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Get a 2nd opinion if needed