Question 1148747
standard error of the sample = square root(0.40 * (1-0.40)/400) = 0.0245
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The percentage of single parent households in the sample will be around
40 give or take 0.0245 or so.
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Since the sample size is greater than 30, we can use the normal distribution's z-tables
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Probability (P) (0.35 < X < 0.45) = P(X < 0.45) - P(X < 0.35)
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z-score(0.45) = (0.45 - 0.40)/0.0245 = 2.04
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P(X < 0.45) = 0.9793
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z-score(0.35) = (0.35 - 0.40)/0.0245 = -2.04
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P(X < 0.35) = 0.0207
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P(0.35 < X < 0.45) = 0.9793 - 0.0207 = 0.9586 is approximately 0.96 or 96%
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