<PRE><B>Question 1148759</B>
.
A boat travelling at full speed against a current goes 14 kph. Travelling at half speed with current goes 10 kph. 
Find the rate of the current and the {{{highlight(cross(maximum))}}} &amp;nbsp;&lt;U&gt;full&lt;/U&gt; &amp;nbsp;speed of the boat in &amp;nbsp;&lt;U&gt;still water&lt;/U&gt;. 
(use x and y variables and show a full solution please)
~~~~~~~~~~~~~~~~~~



&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;Pay attention on how I edited your post to make the formulation precisely correct.



&lt;pre&gt;
Let  &quot;x&quot;  be the &quot;full&quot; speed of the boat in &lt;U&gt;still water&lt;/U&gt;,

and let  &quot;y&quot;  be the rate of the current.


Then the effective rate moving upstream is  (x-y) kph.

     the effective speed moving downstream is   {{{x/2 + y}}} kph.


From the condition,


    x - y = 14  kph   (1)

    {{{x/2}}} + y = 10  kph   (2)


Add the equations (1) and (2).  You will get


    {{{(3/2)x}}} = 14 + 10 = 24,


which implies  x = {{{(2/3)*24}}} = 16 kph.


Then from equation (1),  y = x - 14 = 16 - 14 = 2 kph.


&lt;U&gt;ANSWER&lt;/U&gt;.  The &quot;full&quot; speed of the boat in &lt;U&gt;still water&lt;/U&gt;  is 16 kph;

         the rate of the current is  2 kph.
&lt;/pre&gt;

Solved.


-------------


What you will do with my full solution / solutions ?


Will sell to other web-sites ?



</PRE>