Question 105782
{{{s[1]}}} is the speed for first portion
{{{s[2]}}} is the speed for the 2nd portion
{{{s[1] = s[2]}}}
{{{s[1] = 560/t[1]}}}
{{{s[2] = 480/t[2]}}}
{{{t[1] = t[2] + 1}}}
{{{560/(t[2] + 1) = 480/t[2]}}}
{{{480t[2] + 480 = 560t[2]}}}
{{{80t[2] = 480}}}
{{{t[2] = 6}}}hours answer