Question 1148650
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Sketch the triangle with three its vertices at the given points.


Construct the circle circumscribed around this triangle.


The center of this circle is the point you are looking for.


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The center of this circle is the common intersection point of three  PERPENDICULAR  BISECTORS  to the sides of the triangle.


This point is  EQUALLY  REMOTED  from the three triangle's vertices.


See the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/Triangles/Perpendicular-bisectors-of-a-triangle-sides-are-concurrent.lesson?content_action=edit_dev>Perpendicular bisectors of a triangle sides are concurrent</A>

in this site.